Question

If kx^2-2kx+6=0 has equal root, find k.

Answer 1

Answer:  k = 0   (or)   k = 6

Step-by-step explanation:

$kx^{2} - 2kx + 6$

Now, since they have equal roots,

=>  $Discriminant (D) = b^{2} - 4ac = 0$    where a = k, b = -2k and c = 6

=>  $(-2k)^{2} - 4 (k) (6) = 0$

=>  $4k^{2} - 4 (6k) = 0$

=>  $4k [k - 6] = 0$

=>  $k = 0 \\k = 6$

Hope it helps...

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