Question

if kx^3+9x^2+4x-10 divided by (x+3) leaves remainder 5, find the value of x

Answer 1

Hi,friend!!✌

A good question you have asked.

Here is your answer.
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If , p(x)= kx³+9x²+4x-10

Then, p(-3) = 5 [ By the remainder theorem x-(-3)]

So, k(-3)³+9(-3)²+4(-3)-10 = 5
=> -27k + 81 - 12 -10 = 5
=> -27k + 81 = 5 + 10 + 12
=> -27k= 27-81
=> k = -54\-27
=> k = 2
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Hope you will understand this math. :)

Answer 2

HOPE THIS HELPS YOU

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