If Kx+3y=6 and 2x-3y=12 has no solution then find k
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Given Equation
kx + 3y = 6
2x - 3y = 12 has no Solution
To Find The value of k
For No solution
a₁/a₂=b₁/b₂ ≠ c₁/c₂
Now Compare with
a₁x + b₁y + c₁ = 0
a₂x + b₂y + c₂ = 0
we get
a₁= k , b₁ = 3 and c₁= -6
a₂ = 2 , b₂ = -3 and c₂ = -12
Put the value
k/2 = 3/-3 ≠ -6/-12
We Take
k/2 = 3/-3
k/2 = -1
k = -2
Answer
Value of k = -2
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