If Kx(x-2)-6=0(k is not equal to 0)have two equal roots find the value of K
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◉GIVEN:-
Quadratic equation:- kx( x-2)+6=0
(kx^2 - 2kx + 6 = 0)
◉TO FIND:-
Value of K
◉FORMULA USED:-
b^2 - 4ac = 0 (because this quadratic equation have two equal roots)
◉SOLUTIONS:-
Comparing the given equation with general equation ax^2 + bx + c = 0
We get,
a = k
b = -2k
c = 6
HOPE IT HELPS :)
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