Question

If kx² + (5 + k)x + 5 = 0, k =\ 0 find the roots of the equation.​

Answer 1

Step-by-step explanation:

x={-b+_√(b^2-4ac)}/2a

={-(5+k)+_√((5+k)^2-4k.5)}/2k

={-5-k+_√(25+10k+k^2-20k)}/2k

={-5-k+_√(k^2-10k+25)}/2k

={-5-k+_√(k-5)^2}/2k

={-5-k+_(k-5)}/2k

Now,

x={-5-k+k-5}/2k or x={-5-k-(k-5)}/2k

=(-10)/2k =(-2k)/2k

=(-5)/k =(-k)