Question

If L=50, 41 = 8,42 = 12 and C= 5, then find the mode of the data, where
41 = fm - fm-1 and 42 = fm - fm+1, fm = frequency of modal class, fm-1 =
frequency of class before modal class, fm+1 = frequency of class after modal
class, C = class width.​

Answer 1

Answer:

Here maximum frequency is 20 ,the class corresponding to this 30-40

So modal class is 30-40

Now lower limit of modal class (l)=30

Frequency (f1) of modal class =20

frequency (f0) of preceding the modal class  =12

frequency (f2) of the class succeeding the modal class=11

Class size=10    

Mod=l+[  

2f1−f0−f2

f1−f0

​  

]×h

Mod =30+[  

2×20−12−11

20−12

​  

]×10=30+  

17

8

​  

×10=30+4.705=34.705

Step-by-step explanation: