If l=8cm and b=4cm,then the are of rectangle=???
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☆ Solution ☆
Given :-
- Length ( l ) of the rectangle is 8 cm
- Breadth ( b ) of the rectangle is 4 cm
To Find :-
- The area of the rectangle
Step-by-Step-Explaination :-
As we know that :-
Area of the rectangle = length ( l ) × breadth ( b )
Where,
- Length ( l ) of the rectangle = 8 cm
- Breadth ( b ) of the rectangle = 4 cm
Putting the respective value,
Area of rectangle = 8 × 4
Area of rectangle = 32
Hence,
The area of the rectangle is 32 cm²
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Know More :-
Perimeter of Rectangle = 2( L + B )
Perimeter of square = 4 × Side
Perimeter of triangle = AB + BC + CA
Area of Rectangle = L × B
Area of Square = ( side ) ²
Area of Rhombus = Product of Diagonal/2.
Area of Parallelogram = Base × Height.
Area of triangle = 1/2 × base × height .
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Answered by
50
Correct question :
★ If length is 8cm and breadth is 4cm, then the Area of rectangle ?
Given :
- Length of rectangle = 8 cm
- Breadth of rectangle = 4 cm
To Find :
- Area of rectangle ?
Required Knowledge :
- Now, substitute the values :-
- ⟶ 8 × 4
- ⟶ 32 cm²
■ Hence, the Area of rectangle is 32 cm².
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Some formulas to be remembered :-
- Perimeter of rectangle = 2 ( Length + Breadth )
- Area of rectangle = ( Length × Breadth )
- Perimeter of Square = 4 × Side
- Area of Square = ( Side² )
- Perimeter of Triangle = a + b + c
- Area of Triangle = 1 / 2 × Base × Height
- Area of Parallelogram = Base × Height
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