Question

if L and B are zeroes of polynomial
$p(x) = x2 + x + 1$
then find value of
$\gamma2 + \beta 2$
​

Answer 1

Answer:

$\alpha + \beta = \frac{ - b}{a} = - 1 \\ \alpha \beta = \frac{c}{a} = 1 \\ { \alpha }^{2} + { \beta }^{2} = {( \alpha + \beta )}^{2} - 2 \alpha \beta \\ = {( - 1)}^{2} - 2(1) \\ = 1 - 2 \\ = - 1$