Question

If l and m are the zeroes of polynomial ax^2 + bx + c, then 1/l + 1/m is​

Answer 1

Answer:

(-b/c)

(1/l + 1/m) = ( l+m )/ lm,

by taking LCM of denominator

For ax²+bx+c=0

sum of roots, l+m = (-b/a)

product of roots , l*m = (c/a)

• So, (1/l +1/m) = (-b/a) / (c/a)
• = (-b/c)

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