Question

if l and m are the zeros of polynomial x^2-4x+3 then show that 1/l + 1/m - 2lm + 14/3 = 0​

Answer 1

Answer:

vcx

Step-by-step explanation:

cvx

Answer 2

Answer:

0

Step-by-step explanation:

In x^2-4x+3 do middle term

product as 3 and sum as -4

so the equation will be x^2-x-3x+3

so it will be x (x+1)-3(x-1)

(x-3) (x-1)=0

therefore x = 3 = n

x=1=n

now n/m+1/n-2mn+14/2

1/3+1-6+14/3

(1+3-18+14)/3

(18-18)/3

0/3

=0