Question

if l,b are the zeroes of the polynomial p(x )= 3x²-2x-6 the find 1/l + 1/ b​

Answer 1

Step-by-step explanation:

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(1+α)(1+β)

(1−α)(1−β)

(1+α+β=αβ)

(1−α−β+αβ)

(

1+(α+β)+αβ

1−(α+β)+αβ

)

⎣

⎢

⎢

⎡

1−

3

2

+

3

1

1+

3

2

+

3

1

⎦

⎥

⎥

⎤

[

2

2×3

]=3

=

(1+α+β+αβ)

(1−α)(1+β)+(1−β)(1+α)

=

3

2

1+β−α−αβ+1+α−β−αβ

=23(2−2αβ)

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=3(1−αβ)

=3(1− 31 )

=2

Answer 2

Answer:

$\frac{1}{l} +\frac{1}{b} =\frac{l+b}{lb} =\frac{2/3}{-2} =\frac{-1}{3} \\Sum of zeros=\frac{-b}{a} Product=\frac{c}{a}$

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