Question

If l is a length of a closed pipe containing a gas which vibrates in fundamental mode the wavelength of the wave is

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Answer 1

Both piper vibrate in first overtone. fc = fo 3Vc4L = 2Vo2lo 3Vc4L = Volo VoVc = 3lo4L Also, VoVc = √(ρ1ρ2) Then, √(ρ1ρ2) = 3lo4L lo = 4L3√(ρ1ρ2)

Answer 2

Answer:

Both piper vibrate in first overtone.

fc=fo

4L3Vc=2lo2Vo

4L3Vc=loVo

∴VcVo=4L3lo

Also,

VcVo=ρ2ρ1

Then,

ρ2ρ1=4L3lo

lo

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