If l is a non singular matrix p is a permutation matrix , and b is a given vector, how would you sove lpx=b
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If P is a permutation matrix, and Y = XP, show that Y has the same columns ... Since P1 has the same columns as the identity matrix I .... Use “substitution” to solve Lx = b where. L = ⎡ .
Missing: lpx= | Must include: lpx=
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