if L is twice as good as an and M is twice as good as N and N can do a work in 8 days then find the time taken by all three of them together to finish the work ?
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Answer:
Let the work done by B be x.
∴Work done by A =2x
Work done by A and B together in 14 days =1
Work done by A and B together in 1 day =
14
1
⇒ Work done by A in 1 day + Work done by B in 1 day =
14
1
x+2x=
14
1
⇒3x=
14
1
⇒x=
42
1
Work done by B in 1 day =
42
1
∴ Work done by A in 1 day =
21
1
Hence, to finish the work, A require 21 days.
Hence, A alone can finish the work in 21 days.
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