Question

If l, m are real and l not equals to m then show that the roots of (l-m) x^2 - 5(l+m)x - 2(l-m)=0 are real and unequal​

Answer 1

=25(l+m)

2

+4(l−m)

2

which is always >0

∴it has real and unequal roots

Answer 2

Step-by-step explanation:

Correct option is

C

real and unequal

l,m,n∈Rl=m(l−m)x2−5(l+m)x−2(l−m)=0D=(−5(l+m))2+8(l−m)2

As (l+m)2 and (l−m)2 both greater than zero as l=m so D greater than zero so roots are real and distinct.