Math, asked by rekha316, 1 year ago

if L+M+N=0 and L,M,N are ratinals the roots of the equation (M+N-L)x2+(N+L-M)x+(L+M-N)=0​

Answers

Answered by vyaswanth
1

Answer:

-M/L and N/L

Step-by-step explanation:

  • simplify the given expression so we can get that
  • L+M=-N
  • M+N=-L
  • N+L=-M

  1. NOW SUBSTITUTE THE GIVEN VALUES IN EXPRESSION WE GET
  2. -2Lx²-2Mx-2N=0
  3. we get Lx²+Mx+N=0
  4. NOW WE KNOW ROOTS ARE (-b/a);(c/a)
  5. So ROOTS are -M/L and N/L
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