if L+M+N=0 and L,M,N are ratinals the roots of the equation (M+N-L)x2+(N+L-M)x+(L+M-N)=0
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Answer:
-M/L and N/L
Step-by-step explanation:
- simplify the given expression so we can get that
- L+M=-N
- M+N=-L
- N+L=-M
- NOW SUBSTITUTE THE GIVEN VALUES IN EXPRESSION WE GET
- -2Lx²-2Mx-2N=0
- we get Lx²+Mx+N=0
- NOW WE KNOW ROOTS ARE (-b/a);(c/a)
- So ROOTS are -M/L and N/L
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