Question

If L+M + N = 0 and L, M, N are rationals the roots of the equation
(M+N-L)x²+(N+L-M)x+(L+M-N) = 0 are​

Answer 1

Step-by-step explanation:

Given, (l−m)x2−5(l+m)x−2(l−m)=0

The standard quadratic equation is ax2+bx+c=0 

here,  D=b2−4ac=25(l+m)2+8(l−m)2>0

Therefore, the roots are real and unequal