Math, asked by guptasania13, 2 months ago

If L + M + N = 0 and L, M, N are rationals the roots of the equation (M+N–L)x2+(N+L–M)x+(L+M–N) = 0 are a) real and irrational b) real and rational c) imaginary and equal d) real and equal​

Answers

Answered by llJoyll
0

Answer:

Correct option is

A

Rational

On comparing the given equation with Ax

2

+Bx+C=0 we get,

A=(b+c−a) ; B=(c+a−b) and C=(a+b−c)

We know, D=B

2

−4AC

∴D=(c+a−b)

2

−4(b+c−a)(a+b−c)

=(a+b+c−2b)

2

−4(a+b+c−2a)(a+b+c−2c)

=(−2b)

2

−4(−2a)(−2c)=4(b

2

−4ac)

=4[(−a−c)

2

−4ac]=4(a−c)

2

={2(a−c)}

2

= Perfect square

∴ The roots are rational.

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