If L + M + N = 0 and L, M, N are rationals the roots of the equation (M+N–L)x2+(N+L–M)x+(L+M–N) = 0 are a) real and irrational b) real and rational c) imaginary and equal d) real and equal
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Answer:
Correct option is
A
Rational
On comparing the given equation with Ax
2
+Bx+C=0 we get,
A=(b+c−a) ; B=(c+a−b) and C=(a+b−c)
We know, D=B
2
−4AC
∴D=(c+a−b)
2
−4(b+c−a)(a+b−c)
=(a+b+c−2b)
2
−4(a+b+c−2a)(a+b+c−2c)
=(−2b)
2
−4(−2a)(−2c)=4(b
2
−4ac)
=4[(−a−c)
2
−4ac]=4(a−c)
2
={2(a−c)}
2
= Perfect square
∴ The roots are rational.
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