If l+m+n =0 and l,m,n are the rationals the roots of the equatiobn (m+n-l)x2+(n+l-m)x+(l+m-n)=0 are..give reason also a)real nd rational b)real and irrational
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8
The answer is a. It is real and rational
Divyankasc:
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Answered by
33
(m + n - l)x2 + (n + l - m)x + (l + m - n) = 0
As l + n + m = 0
So using this in the quadratic equation we get
-2lx2 - 2mx - 2n = 0
Or lx2 + mx + n = 0
As l , m and n are rational so roots are rational for the above quadratic equation.
Hence option a ) is correct.
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