If, l, m, n are three lines such that l||m and n⊥ l, prove that n⊥ m.
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Given : l, m, n are three lines such that l || m and n ⊥ l.
To prove: n ⊥ m
Proof :
Since, n ⊥ l
⇒ ∠1 = 90° ………….(1)
Now, l ‖ m and transversal intersects them.
∠2 = ∠1 ………(2)
Thus, the corresponding angles made by the transversal n with lines l and m are equal.
From eq (1) & (2) , we get ∠2 = ∠1 = 90°
⇒ ∠2 = 90°
Hence, n is perpendicular to m (n ⊥ m).
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Given:
l || m and n⊥ l
To prove:
n⊥ m
Proof:
If l || m, and n⊥ l:
Angle formed by n on l will be equal to 90°
And when l || m, corresponding angles are equal. Thus:
Angle formed by n on m will also be equal to 90°
Therefore, n⊥ m.
Hence Proved.
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