Question

if L-M-N
length of (MN)=5√5 length of (LM) = 2√5 find length of (LN)​

Answer 1

Step-by-step explanation:

in the given fig. n, l, and m are the length of the side LM, MN, and NL, of right angled triangle LMN...If r is the radius of the incircle, then Prove that 2r=(n+l-m)

Answer 2

Answer:

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