If l parallel m and n is a transversal such that angle 8: angle 5 =13:5 find all the angles
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let angle 8 and angle 5 be 13x° and 5x°.
angle 8 + angle 5 = 180 (Linear Pair of angles)
13x° + 5x° = 180°
18x = 180°
x = 180°/18
x = 10°
Hence, angle 8 = angle 6 = 13x° = 130°(Vertically opposite angles)
angle 5 = angle 7 = 5x° = 50° (vertically opposite angles)
let angle 4 be x°.
angle 4 + angle 5 = 180°
x° + 50° = 180°
x° = 180° - 50°
x = 130°
angle 4 = 130°
the rest of the answer is in the pic...
sry for the inconvenience..
hope uhh got some help....
angle 8 + angle 5 = 180 (Linear Pair of angles)
13x° + 5x° = 180°
18x = 180°
x = 180°/18
x = 10°
Hence, angle 8 = angle 6 = 13x° = 130°(Vertically opposite angles)
angle 5 = angle 7 = 5x° = 50° (vertically opposite angles)
let angle 4 be x°.
angle 4 + angle 5 = 180°
x° + 50° = 180°
x° = 180° - 50°
x = 130°
angle 4 = 130°
the rest of the answer is in the pic...
sry for the inconvenience..
hope uhh got some help....
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dont know what can i do unit
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