Question

If lal = 3 |b| = 4 & la+bl = 5 the la-bl=​

Answer 1

Step-by-step explanation:

Given |A - B| = (A - B) ==>

(A - B)^2 = (A - B)^2 or

A^2 + B^2 - 2A•B = A^2 + B^2 - 2A.B ==> A^2 + B^2 - 2AB cost = A^2 + B^2 - 2A.B ==> cost = 1 ==> t = 0 degree. So, one of the vectors A, B should be a scalar multiple of the other.

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