if Lambda and beta are the zeros of a quadratic polynomial such that Lambda plus beta is equal to 24 and Lambda minus beta 8 find the quadratic equation having a Lambda and beta as its zeros
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lambda + beta =24 ------(1)
lambda - beta =8--------(2)
adding equations 1 &2
2( lambda) =24+8
lambda = 32÷ 2 = 16
substitution of lambda in any of the equations gives us the value of beta
according to the equations if lambda = 16 then beta = 8
we know that if lambda and beta are the roots of quadratic
equation then the quadratic equation = x^2 + (lambda +beta)x + ( lambda) (beta)
we know the values of lambda and beta so we can find sum of the roots and product of the roots
lambda + beta = 24 and lambda × beta = 128
so the quadratic equation = x^2 + 24x + 128
I think this is the answer
hope it helps u
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Answer:
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Explanation:
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