if lamda knot is the threshold wave length for photoelectric emission, lamda the wave length of light falling on the surface of a metal and m the mass of the electron , then the velocity of ejected electron is given by -
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your answer is given in the pic attached
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its right but answer is {2hc/m(lamda knot - lamda/ lamda knot × lamda)}raise to power 1/2
please help me
can u just right the answer on a paper and then upload its pic cuz i can't understand the formula in the language form that you have written above
y did u report my answer
ok
y did u report My answer
i have send pic of answer in question u can see now
i have send pic of answer in question u can see now
i have send pic of answer in question u can see now
where is the pic
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