If latrel surface area of cube is increased by 44 percent . find the percentage change in the volume of the cube
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Answer:
Answer
Correct option is
B
125
Let the original side be a then
Original surface area S=6a
2
When side is increased by 50%, side becomes
2
3
a then
Surface area s=
2
27
a
2
Hence,
Surface area is increases by x=
6a
2
2
27
a
2
−6a
2
×100=125%
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