Question

If law of conservation of mass was to hold true, then 20.8 g of BaCl2 on reaction with 9.8 g
of H2SO4, will produce 7.3 g of HCI and BaSO4 equal to
a) 11.65 g
b) 23.3 g
c) 25.5 g
d) 30.6 g
41 15 9 of hydroca​

Answer 1

Answer:

B.) 23.3

Explanation:

BaCl

2

+H

2

SO

4

⟶BaSO

4

+2HCl

1 mole of BaCl

2

reacts with 1 mole of H

2

SO

4

to give 1 mole of BaSO

4

and 2 moles of HCl.

Here, moles of BaCl

2

=

208

20.8

= moles of H

2

SO

4

=

98

9.8

=0.1

∴ Moles of BaSO

4

formed =0.1

∴ Mass of BaSO

4

formed =0.1×233=23.3g

i.e. 20.8+9.8=7.3+23.3=30.6

Hence the correct option is B.

I hope this will help u

so please mark as brainliest answer

Answer 2

Let mass of BaSO4 = x

20.8 + 9.8 = 30.6

30.6 - 7.3 =23.3 gm

mass of BaSO4 = 23.3 gm