Question

if Lbsquare + M square=13,L+m=5 then find the value of L M
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Answer 1

Step-by-step explanation:

${l}^{2} + {m}^{2} = 13 \\ l + m = 5 \\ (l + m) ^{2} = {l}^{2} + {m}^{2} + 2lm \\ {5}^{2} = 13 + 2lm \\ lm = \frac{25 - 13}{2} \\ = \frac{12}{2} \\ = 6$

Answer 2

given

$= > l {}^{2} + m {}^{2} = 13..(1 \\ \\ = > l + m = 5...(2$

solution

square of eqution (1

$= > (l + m) {}^{2} = (5) {}^{2} \\ \\ = > l {}^{2} + m {}^{2} + 2ml = 25..(3 \\ \\ now \: eq \: (1 \: value \: put \: on \: eq \: (3 \\ \\ = > 13 + 2ml = 25 \\ \\ = > ml = \frac{25 - 13}{2} \\ \\ = > ml = \frac{12}{6} \\ \\ lm = 6$

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formula uses

$= > (a + b) {}^{2} = a {}^{2} + b {}^{2} + 2ab$

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I hope it helps you