Question

If LCM(a, b) = 12 and HCF(a, b)= 2 then a²b² is equal to​

Answer 1

Step-by-step explanation:

LCM(a,b)+HCF(a,b) = a× b

12+2=a×b

14=ab ------equation 1

a²b²

= (ab)(ab)

= 14×14 [from equation 1]

= 196

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Answer 2

Answer:

The answer for your question is 576

Step-by-step explanation:

LCM(a,b)=12

HCF(a,b)=2

$a^{2} b^{2}$= ?

as we know that the product of HCF*LCM = product of the two numbers

2*12=a*b

24=a*b

we are not given with values of a and b so we continue with trial and error method that is by inserting values of a,b to equal it to 24

we know that 12*2 = 24 , it is also equal to 24 , i.e, 24 = 12*2(24)

let us assume that a = 12 and b = 2 , we have to check if the lcm of (a,b) = 12 as given

lcm (12,2) = 12 and we have to check for  hcf (a,b) = 2 and hcf (12,2) = 2

so , we can thereby conclude that the values of a and b are 12 and 2 respectively , or you can also take vice versa that is b =12 and a = 2 , NO MATTER WHAT VALUES YOU TAKE FOR A AND B , MAKE SURE THAT LCM * HCF = THE PRODUCT OF 2 NO'S

ACCORDING TO THE QUESTION :- WE HAVE TO FIND $a^{2} b^{2}$

AS WE KNOW THAT VALUES OF A AND B SUBSTITUTE 12*12*2*2=576

SO WE CAN CONCLUDE THAT OUR ANSWER IS 576

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