If LCM & HCF of two numbers are 672 & 6 respectively. If one number is 42 then the
other number is:
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Now, divide l/h into two co prime numbers and set them equal to x and y. so, x and y are 2 and 3 and thus the numbers are 8 and 12. Divide lcm by hcf then factor that and any factorization you get can be put into two numbers that when each multiplied by hcf give you a number in a pair.
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sorry can i answer your question after some time
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