if lcm and hcf of three number are 90 and 7. two number are 15 and 30.find the third number
brunoconti:
the question is not right. since 7 is not a factor of neither 15 nor 30. then the hcf cannot be 7!!!!!
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hcf*lcm=product of no
let the third no be x
90*7=15*30*x
x=1.5.......................ans
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