Question

If LCM and HCF of two numbers is 2 and 60 respectively and one number is 20, Find other number ? (a) 6 (b) 4 (c) 12 (d) 10
[tex]If LCM and HCF of two numbers is 2 and 60 respectively and one number is 20, Find other number ?
\ \textless \ br /\ \textgreater \ (a) 6 (b) 4 (c) 12 (d) 10[/tex]
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Answer 1

Answer:

The correct answer is Option A .6

Step-by-step explanation:

HCF× LCM= PRODUCT OF TWO NUMBERS

60×2=20×?

120÷20=6

Answer 2

In context to questions asked,

We have to determine the value second number.

As per questions,

We have,

LCM of the given number = 2

HCF of the given number = 60

Value of first number = 20

As we know that,

$lcm \times hcf = product \: of \: two \: numbers$

So, putting the value of given numbers in required equation,

We will get,

value of second number will be = (60 × 2)/20 = 120/20 = 6.