Math, asked by ambicaparasa1883, 1 year ago

If lcm and hcf of two nunver is 864 and 36 find other numver if one is 108

Answers

Answered by fabinachristiana1
0

Answer:

Step-by-step explanation:

LCM=864, Hcf=36 and one number(x)=108,other number(y)=?

Now,

LCM(x,y)×HCF (x,y) =xy

864×36=108×y

864×36÷108=y

31104÷108=y

288=y

Therefore, second number is 288

Answered by barnadutta2015
0

Answer: The other number is 288 if LCM and HCF of two numbers is 864 and 36 and one of the number is 108.

Step-by-step explanation:

Given in the question that

LCM of two numbers=864

HCF of two numbers=36

one number(x)=108

other number(y)=?

Any two provided natural numbers' LCM and HCF products have the same value as the supplied numbers' products.

So, we have to find the other number i.e. y

Now,

Using the formula

LCM(x,y)×HCF (x,y) = Product of two numbers

⇒864×36 = 108×y

⇒864×36 = 108×y

⇒31104  = 108×y

⇒y = 31104 ÷ 108

⇒ y = 288

Therefore, second number is 288.

To know more, click here:

https://brainly.in/question/31596084

https://brainly.in/question/776057

#SPJ5

Similar questions