Question

If LCM of 2 numbers is 48 and HCF is 1 then how many possible pair of numbers are possible?

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Answer 1

Step-by-step explanation:

Let the two numbers be x and y.

HCF×LCM=Product of the two numbers

1×48=xy

xy=48

The number of possible pairs are

(1,48);(2,24);(3,16);(4,12);(6,8)

(48,1);(24,2);(16,3);(12,4);(8,6)

But it should satisfy the condition HCF=1

So, possible pairs are

(1,48);(48,1);(3,16);(16,3)

Whose HCF=1 and LCM=48

So,there are 4 possible pairs

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