If LCM of first 10 natural numbers
is 2^a.3^b.5^.7^d then find
a + b + c + d .
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Answer:7
Step-by-step explanation:
LCM OF FIRST 10 NATURAL NUMBERS IS 2520
2520=2*2*2*3*3*5*7
SO,2^2*3^2*5^1*7^1=2520
2^a*3^b*5^c*7^d
2^2*3^2*5^1*7^1
Compare these
You get,
a=2
b=3
c=1
d=1
a+b+c+d=2+3+1+1
=7
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