If Lcm of two no. Is 2079 and their HCF is 27 if one of the numbers is 297 find the other no.
Answers
Answered by
27
let the other no. is Y
then
LCM × HCF = 297× Y
2079×27 = 297 × Y
Y = (2079×27) / 297
Y = 189
hence the other no. is 189
then
LCM × HCF = 297× Y
2079×27 = 297 × Y
Y = (2079×27) / 297
Y = 189
hence the other no. is 189
Answered by
13
LCM X HCF= product of two numbers
2079 x 27= 297 x other number
56133 divided by 297= other number
189 = to the other number.
verification -
2079 x27= 297 x 189
56133 = 56133
2079 x 27= 297 x other number
56133 divided by 297= other number
189 = to the other number.
verification -
2079 x27= 297 x 189
56133 = 56133
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