CBSE BOARD X, asked by Tejaswini8937, 1 year ago

If Lcm of two no. Is 2079 and their HCF is 27 if one of the numbers is 297 find the other no.

Answers

Answered by realsujaykumar
27
let the other no. is Y
then
LCM × HCF = 297× Y
2079×27 = 297 × Y
Y = (2079×27) / 297
Y = 189
hence the other no. is 189
Answered by riddhiya
13
LCM X HCF= product of two numbers

2079 x 27= 297 x other number

56133  divided by 297= other number

189 = to the other number.

verification -

2079 x27= 297 x 189

56133 = 56133
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