Question

if lcm of two numbers is 10 and their HCF is 1/21 if one of the number is 2/7 then the other number is
​

Answer 1

Answer:

Let the other number be x

Now, we know that

product of two numbers = product of HCF and LCM

=> 2/7 * x = 1/21 * 10

=> x = 10/21 * 7/2

=> x = 5/3

Hence, the required number is 5/3.