if lcm of two numbers is 36 and hcf is 2 and one of the number is 18,find other numbrt
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Answered by
1
product of two numbers=LCM× HCF
18× x = 36× 2
where x is the another number
now
x= 36×2/18
x=4
here is your answer...
hope this helps you
18× x = 36× 2
where x is the another number
now
x= 36×2/18
x=4
here is your answer...
hope this helps you
Answered by
1
Fact : HCF * LCM = Product of two numbers
Let the two numbers be ' a ' and ' b '.
Given that, HCF = 2, LCM = 36, ' a ' = 18.
To find, ' b ' = ?
Solution : Substituting in the formula we get,
2 * 36 = 18 * b
=> 72 = 18 * b
=> b = 72 / 18
=> b = 4
Hence the other number is 4.
Hence the two numbers are 2 and 4.
Hence solved !
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