Question

if lcm of two prime numbers a and b(a>b) is 667 then the value of 7b-5a is ​

Answer 1

Answer:

7b-5a=16

Step-by-step explanation:

a and b are prime numbers

so LCM (a.,b)=a*b

so 667=a*b

667=23*29

so a*b=23*29

a > b so a=29 and b=23

Thus 7b-5a=7*23-5*29

=161-145

=16

Answer 2

Answer:

the value of 7b-5a is ​16

Given:

lcm of two prime numbers a and b(a>b) = 667

To find:

the value of 7b-5a

Solution:

to find the prime numbers whose lcm is 667, we must do the prime factorization of 667.

667 = 23 x 29

so, a= 29 ; b=23  [since a>b (given)]

let 7b-5a be X.

so,

7b-5a = X

[7 x 23] - [5 x 29] = X

161- 145 = X

X = 16

Hence, 16 is the correct answer.

#SPJ2