Math, asked by rahulkk9360, 6 hours ago

If LCM of x and 18 is 36 and HCF of x and 18 is 2, x=

Answers

Answered by theparvezalm
0

Answer:

HCF(a,b)*LCM(a,b)=a*b

2*36=x*18

x=4

Answered by LaeeqAhmed
0

  \blue{ \boxed{ \sf product \: of \: numbers = LCM \times HCF}}

 \implies 18×x = 36 \times 2

 \implies 18x = 72

 \orange{ \therefore x = 4}

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