Question

if leangth of rectangle park is 22m and its area is 286m² find its width and perimeter​

Answer 1

Answer :-

Given :-

• Length of park = 22 m
• Area = 286 m²

To Find :-

• Width
• Perimeter

Solution :-

We know that,

→ Area = Length × Width

Substituting the values of area and length in formula :-

→ 286 = 22 × w

→ w = 286 / 22

→ w = 13

Width of park = 13 m

Calculating Perimeter :-

We know that,

→ Perimeter = 2 ( Length + Width )

Substituting the values in formula :-

→ Perimeter = 2 ( 22 + 13 )

→ Perimeter = 2 ( 35 )

→ Perimeter = 70

Perimeter of park = 70 m

Answer 2

Answer:

Given:-

If length of rectangle park is 22m and its area is 286m². Find its width and perimeter.

To Find:-

The width and perimeter.

Note:-

●》Area = length × width when it is transposed, Width = $\frac{Area}{Length}$.

●》After finding width, Perimeter of rectangle park = 2 × ( Length + width ).

Solution:-

[ First, Width ]

$\huge\red{Length = 22m, its \ \ Area = 286m², Width = ?}$

☆ According to note first point~

▪︎$Width = \frac{Area}{Length}$

▪︎$Width = \frac{286m²}{22m}$

☆ After dividing and square will be canceled from metre~

▪︎$Width = 13m$

$\huge\pink{Width = 13m}$

_______________________________

[ Now, Perimeter ]

$\huge\red{Length = 22m, Width = 13m}$

☆ According to note second point~

▪︎$Perimeter \ \ of \ \ rectangle \ \ park = 2 × ( Length + Width )$

▪︎$Perimeter \ \ of \ \ rectangle \ \ park = 2 × ( 22m + 13m )$

▪︎$Perimeter \ \ of \ \ rectangle \ \ park = 2 × 35m$

☆ After multiplying~

▪︎$Perimeter \ \ of \ \ rectangle \ \ park = 70m$

$\huge\pink{Perimeter \ \ of \ \ rectangle \ \ park = 70m}$

Answer:-

Hence,

• Width = 13m
• Perimeter of rectangle park = 70m.

:)