Question

If \left|\begin{array}{lll}a & b & c \\ b & c & a \\ c & a & b\end{array}\right|=k(a+b+c)\left(a^{2}+b^{2}+c^{2}-a b-b c-c a\right) ∣ ∣ ∣ ∣ ∣ ∣ ​ a b c ​ b c a ​ c a b ​ ∣ ∣ ∣ ∣ ∣ ∣ ​ =k(a+b+c)(a 2 +b 2 +c 2 −ab−bc−ca) then k=k=

Answer 1

Answer:

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