Question

if length =4cm breadth=4cm height =4cm then find the LSA and TSA of the cuboid ​

Answer 1

Answer:

(1) length =12 cm breadth =10 cm  height =5 cm

TSA=2(lb+bh+lh)=2[12×10+10×5+5×12]

TSA=2[120+50+60]=2×230

[TSA=460cm2]

(2) length =5 cm   breadth =3.5 cm   height =1.4cm

TSA=2(lb+bh+lh)=2[5×3.5+3.5×14+1.4×5]

TSA=2[17.5+4.90+7.0]=2[29.4]

[TSA=58.8cm2]

(3) length =2.5 cm   breadth =2 m   height =2.4 m

TSA=2(lb+bh+lh)=2[0.025×2+2×2.4+2.4×0.025]

TSA=2[0.05+4.8+0.0600]=2[4.91]

(4) length =8 m   breadth =5 m    height =3.5 m

TSA=2(lb+bh+lh)=2[8×5+5×

Step-by-step explanation:

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Answer 2

Given :-

• Length = 4cm
• Breadth = 4cm
• Height = 4cm

Solution :-

TSA = 2( lb + bh + lh)

= 2(4*4 + 4*4 + 4*4)

= 2(16 + 16 + 16)

= 2(48)

TSA = 96cm²

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