if length and breadth of a rectangle are 7 cm and 16 cm respectively compare its perimeter and area
Answers
1. Area of rectangle with length 16 cm & width 4 cm
=(length)×(width)
=(16)(4)
=64 cm2
2. Area of square of side x= area of rectangle with length 16 cm & width 4 cm
x2=16×4
x2=64
x=64−−√=8
3. Perimeter of square of side x=8 cm is
=4x
=4(8)
=32 cm
Continued …
Perimeter of the square = 4*side
= 4* 8 = 32
The area of the rectangle =64 cm^2
The value of x =8 cm
The perimeter of the square = 32 cm
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Given: -
Length of Rectangle = 7 cm
Width of Rectangle = 16 cm
To Find: - Perimeter and area of the rectangle.
Solution: -
Given that the length of rectangle = l = 7 cm
and Width of rectangle = b = 16 cm
We know the area of rectangle = l x b = 7 x 16 = 112 sq.m
Also the perimeter of rectangle = 2 x (l + b)
= 2 x ( 7 + 16 ) = 46 m
Therefore the area and perimeter of rectangles are 112 sq.mand 46 m respectively. Both area and perimeter are dependent on the dimensions of rectangle. If one is area of perimeter is higher than the other will also be higher.
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