If length and breadth of a rectangle are doubled how many times of the perimeter the old rectangle will that of new rectangle be?
Answers
Answered by
1
Answer:
The new rectangle = 2 times the old rectangle
Step-by-step explanation:
PLEASE SELECT MY ANSWER AS THE BRAINLIEST ANSWER.
Answered by
2
LET THE LENGTH OF OLD RECTANGLE BE x .
LET THE BREADTH OF OLD RECTANGLE BE y .
NOW THE LENGTH AND BREADTH BOTH IS DOUBLED OF THE LENGTH AND BREADTH GIVEN IN OLD RECTANGLE.
SO THE LENGTH OF THE NEW RECTANGLE IS 2x .
BREADTH OF NEW RECTANGLE IS 2y .
SO PERIMETER OF OLD RECTANGLE = 2(l + b)
= 2(x + y) ........ (1)
NOW PERIMETER OF NEW RECTANGLE
= 2(2x + 2y) ........ (2)
NOW DIVIDE (2) BY (1) , WE GET
= 2(2x + 2y)
_________
2(x + y)
SO THERE WILL BE 2 LEFT AFTER DIVIDING THIS.
SO YOUR ANSWER IS THE PERIMETER IS INCREASED BY TWO TIMES THAT OF OLD RECTANGLE TO THE NEW RECTANGLE.
HOPE THIS ANSWER HELPS YOU!!!!!
REGARDS,
LET THE BREADTH OF OLD RECTANGLE BE y .
NOW THE LENGTH AND BREADTH BOTH IS DOUBLED OF THE LENGTH AND BREADTH GIVEN IN OLD RECTANGLE.
SO THE LENGTH OF THE NEW RECTANGLE IS 2x .
BREADTH OF NEW RECTANGLE IS 2y .
SO PERIMETER OF OLD RECTANGLE = 2(l + b)
= 2(x + y) ........ (1)
NOW PERIMETER OF NEW RECTANGLE
= 2(2x + 2y) ........ (2)
NOW DIVIDE (2) BY (1) , WE GET
= 2(2x + 2y)
_________
2(x + y)
SO THERE WILL BE 2 LEFT AFTER DIVIDING THIS.
SO YOUR ANSWER IS THE PERIMETER IS INCREASED BY TWO TIMES THAT OF OLD RECTANGLE TO THE NEW RECTANGLE.
HOPE THIS ANSWER HELPS YOU!!!!!
REGARDS,
Similar questions