Math, asked by solutions9636, 7 months ago

If length and breadth of a rectangle are doubled how many times of the perimeter the old rectangle will that of new rectangle be?

Answers

Answered by SidhantVerma77
1

Answer:

The new rectangle = 2 times the old rectangle

Step-by-step explanation:

PLEASE SELECT MY ANSWER AS THE BRAINLIEST ANSWER.

Answered by shubham724517
2
LET THE LENGTH OF OLD RECTANGLE BE x .
LET THE BREADTH OF OLD RECTANGLE BE y .

NOW THE LENGTH AND BREADTH BOTH IS DOUBLED OF THE LENGTH AND BREADTH GIVEN IN OLD RECTANGLE.

SO THE LENGTH OF THE NEW RECTANGLE IS 2x .
BREADTH OF NEW RECTANGLE IS 2y .

SO PERIMETER OF OLD RECTANGLE = 2(l + b)
= 2(x + y) ........ (1)
NOW PERIMETER OF NEW RECTANGLE
= 2(2x + 2y) ........ (2)

NOW DIVIDE (2) BY (1) , WE GET

= 2(2x + 2y)
_________

2(x + y)

SO THERE WILL BE 2 LEFT AFTER DIVIDING THIS.

SO YOUR ANSWER IS THE PERIMETER IS INCREASED BY TWO TIMES THAT OF OLD RECTANGLE TO THE NEW RECTANGLE.



HOPE THIS ANSWER HELPS YOU!!!!!

REGARDS,
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