Question

if length and breadth of a rectangle is increased by 5% and 8% respectively, find the % change in the area of rectangle

Answer 1

Answer:

there will be a increase of 40% in the area of rectangle

Answer 2

Answer:-

Percent of change in Area = 13.4%

Given:-

• Length increased = 5%

• Breadth incresed = 8%

To Find:-

• Percent of change in area of rectangle

Solution :-

Let the

• Length of original rectangle = x

• Breadth of original rectangle = y

Then,

• Area of Original Rectangle = xy

Now,

Length of New Rectangle

$= > x + \frac{5x}{100} \\ \\ = > x + \frac{x}{20} \\ \\ = > \frac{21x}{20}$

Breadth of New Rectangle

$= > y + \frac{8y}{100} \\ \\ = > y + \frac{2y}{25} \\ \\ = > \frac{27y}{25}$

Now,

Area of New Rectangle =

$= > \frac{21x}{20} \times \frac{27y}{25} = \frac{567xy}{500}$

Increase in area

$= > \frac{567xy}{500} - xy \\ \\ = > \frac{567xy - 500xy}{500} \\ \\ = > \frac{67xy}{500}$

Percent Increase

$= > \frac{ \frac{67xy}{500} }{xy} \times 100 \\ \\ = > \frac{67xy}{500} \times \frac{1}{xy} \times 100 \\ \\ = > \frac{67}{5} = 13.4$

Percent Increase = 13.4%