Question

If length and breadth of a room is 15 m
17 cm and 9 m 2 cm respectively. What is
the minimum number of square tiles which
is fit for that?
(1) 820
(2) 841
(3) 840
(4) 814​

Answer 1

The number of tiles required is 814 tiles.

Option (D) is correct.

Step-by-step explanation:

• Length of the room

= 15 m 17 cm

= 15 × 100 + 17

= 1517 cm.

• Breadth of the room

= 9 m 2 cm

= 902 cm.

The HCF of the 1517 and 902 will be size of square tiles.

HCF 1517 and 902 = 41 cm.

• Area of the room

= length × breadth

= 1517 × 902 cm^2

• Area of tiles = 41 × 41 cm^2

So, number of tiles required

= 1517×902 / 41×41

= 814 tiles

Hence the number of tiles required is 814 tiles.

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Answer 2

Given: Length = 15 m 17 cm, Breadth = 9 m 2 cm

To find: minimum number of square tiles to be fit

Solution:

• So now, first we need to convert the length and breadth in cm from m, we get:

• Length of the room= 15 m 17 cm

                = 15 × 100 + 17

                = 1517 cm.

• Breadth of the room= 9 m 2 cm

                = 902 cm.

• The highest common factor of length and breadth of the room will be the number of square tiles required.

• So the highest common factor is: 41

• So now, lets find the area of the room=

                = length × breadth

                = 1517 × 902

• Now,

• Area of tiles required= 41 × 41 cm^2

• So, number of tiles required are:

                   area of room/area of tiles

                   = 1517×902 / 41×41

                   = 814 tiles

Answer:

            So the number of tiles required are 814 tiles.