Question

If length breath and hight of a room is 5m,4m,3m respectively . find cost of white wash the wall and celling at the rate of 17.5/m²​

Answer 1

Answer:-

The cost of whitewashing the walls of the room and ceiling will be equal to the area of the room to be whitewashed multiplied by the rate of the whitewashing per m^2. Thus, the cost of whitewashing the walls of the room and the ceiling is ₹555.

MARK AS BRAINLIEST

Answer 2

Answer:

Given: The length, breadth, and height of a room are 5 m, 4 m, and 3 m respectively.

Since the four walls and ceiling are to be whitewashed so, it has 5 faces only, excluding the base.

Hence, the area of the room to be whitewashed can be obtained by adding the area of the ceiling to the lateral surface area of the cuboidal room.

Lateral surface area of cuboid = 2(l + b)h

Step-by-step explanation:

Length, l = 5 m

Breadth, b = 4 m

Height, h = 3 m

Surface area of 5 faces = Area of the 4 walls and ceiling = lb + 2(l + b)h

lb + 2(l + b)h = (5 m × 4 m) + 2 × (5 m + 4 m) × 3 m

= 20 m² + 2 × 9 m × 3 m

= 20 m² + 54 m2

= 74 m²

The cost of whitewashing the walls of the room and ceiling = Rate × Area

= ₹ 7.50 / m² × 74 m2

= ₹ 555

Thus, the cost of whitewashing the walls of the room and the ceiling is ₹555.