Question

if length of 1 tile is 30 cm and breadth is 25 cm and there is a floor of length 7m and breadth 6m30cm so how many tiles will be needed to cover the floor​

Answer 1

Step-by-step explanation:

area of 1 tile = 30×25 = 750cm^2

length of room = 7m = 700 cm

breadth of room = 650 cm

area of room = l × b = 455000 cm^2

no of tiles = area of room / area of 1 tile

= 455000/750= 1820/3= 606

Answer 2

Step-by-step explanation:

Given length of one tile:

l = 30 cm

b = 25cm.

therefore the area of one rectangular tile is

( l×b )

( 30 × 25) cm^2

750 cm^2

therefore the area of tile is 750cm^2.

A.Q , Given room

l = 7m

b = 6m30cm.

let covert metre into centimeter

so, 7m = 700cm

6m30cm =630cm.

therefore the area of the room is

(700× 630)

=441000 cm^2 .

Given area of one tile is 750cm^2

therefore the no.of tile needed to cover the floor are:

( 441000/750) cm^2

= 588.

so the no.of tile required to cover the room is 588.