If length of = 6800A° then calculate no. of helix no. of base pairs and no. of nucleotide.
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The distance between consecutive nitrogenous bases is 3.4 A°.
68 A° means the DNA strand has 68 ÷ 3.4 = 20 base pairs.
Each base pair has 2 bases, hence there are 40 bases.
As we know, 4 nucleotides form 2 base pairs then 40 nucleotides can form 20 base pairs.
So, the correct option is '40'
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